Counting different word frequency in a string using c++?

I've to make a program to find the frequency of different words in a string that may contain spaces in sorted way. like if I've string


"dsaa wbaa sc" the output must be:


4a 1c 1d 2s 1w

Counting different word frequency in a string using c++?
Here you go:





#include%26lt;iostream%26gt;





using namespace std;





int main()


{





int alp[25]; //for 26 alphabets


int j;


for(j=0;j%26lt;26;j++)


alp[j]=0;





char str[20];


cout%26lt;%26lt;"Enter a string of max 20 char: ";


cin.getline(str,20);





int i;


for(i=0;i%26lt;strlen(str);i++)


{


if(str[i] != ' ')


++alp[str[i] - 'a'];


}





for(i=0;i%26lt;26;i++)


{


if(alp[i] != 0)


cout%26lt;%26lt;alp[i]%26lt;%26lt;(char)('a'+i)%26lt;%26lt;" ";


}





free(str);





return 0;


}





Hope this helps!
Reply:You can do this pretty easily using the STL map data-structure.





example accumulator





std::map%26lt;std::string, int%26gt; count = std::map%26lt;std::string,int%26gt;()


std::string tmpStr;


while(/* there is input */){


/*read tmpStr */


count[ tmpStr ]++;


}





...





output


std::cout %26lt;%26lt; String %26lt;%26lt; "\t" %26lt;%26lt; Count %26lt;%26lt; std::endl;


for (std::map%26lt;%26lt;:std::string, int%26gt;::iterator it = count.begin(); it != count.end(); ++i){


std::cout %26lt;%26lt; it-%26gt;first %26lt;%26lt; "\t" %26lt;%26lt; it-%26gt;second %26lt;%26lt; std::endl;


}